MATH SOLVE

3 months ago

Q:
# Larry bird made 90% of this free throws during his professional career. to simulate one free throw shot by larry bird, we could use a random digit where

Accepted Solution

A:

The complete question gives you three options:

A) odd = made, even = missed.Β

B) 1 to 9 = made, 0 = missed.Β

C) 0 to 4 = made, 5 to 9 = missed.

You need to understand which of these options represent a 90% probability to make the throw.

Let's see the options, considering that the total number of 1-digits is 10:

a) there are 5 odd digits, therefore the probability would be 5/10 = 0.5, which is 50%. Hence, this option is not correct.

b) there are 9 digits between 1 and 9, therefore the probability would be 9/10 = 0.9, which is 90%. Hence, this option is valid.

c) There are 5 digits between 0 and 4, therefore the probability would be 5/10 = 0.5, which is 50%. Hence, this option is not correct, as option a.

Therefore, the correct answer is B) 1 to 9 = made, 0 = missed.

A) odd = made, even = missed.Β

B) 1 to 9 = made, 0 = missed.Β

C) 0 to 4 = made, 5 to 9 = missed.

You need to understand which of these options represent a 90% probability to make the throw.

Let's see the options, considering that the total number of 1-digits is 10:

a) there are 5 odd digits, therefore the probability would be 5/10 = 0.5, which is 50%. Hence, this option is not correct.

b) there are 9 digits between 1 and 9, therefore the probability would be 9/10 = 0.9, which is 90%. Hence, this option is valid.

c) There are 5 digits between 0 and 4, therefore the probability would be 5/10 = 0.5, which is 50%. Hence, this option is not correct, as option a.

Therefore, the correct answer is B) 1 to 9 = made, 0 = missed.